本文将带你了解Maya教程之maya python 定时器多线程问题，希望本文对大家学Maya有所帮助

在maya实现一下python定时器线程控制
    不过简单的可行，建立物体等操作会有崩溃问题发生
    并报出 r6025 pure virtual function call或者'Cannot convert data of type string[]   to type string
    然后就崩溃了
    但是平常的移动之类没什么问题
    可以用来刷新一些东西
    另外这种方法不会阻塞maya的主线程，也就是说你可以一边操作一边看
    以下代码操作注意有可能会导致maya崩溃
   
    import threading as thdimport timeimport maya.cmds as cmds global aaaaaa =   1def fn():    global aaa    aaa += 1      cmds.polySphere(n='mySphere'+str(aaa),sx=1, sy=1, r=1)    cmds.select( clear=True )    thd.Timer(1,fn).start() fn()
   
    上面的就会崩溃
    下面的就不会，估计是创建的问题（需要新建一个叫sphere的物体）
   
    import threading as thdimport timeimport maya.cmds as cmds global aaaaaa =   1def fn():    global aaa    aaa += 1    cmds.setAttr( 'sphere.translateX', aaa   )    cmds.select( clear=True )    thd.Timer(1,fn).start()   fn()然后下面是可以使用的定时器，但是关闭后无法重开from threading import Timer,Thread,Eventimport   time class myTimer():    def   __init__(self,t,hFunction):        self.t=t      self.hFunction =   hFunction      self.thread =   Timer(self.t,self.handle_function)      def handle_function(self):        self.hFunction()        self.thread = Timer(self.t,self.handle_function)      self.thread.start()    def start(self):      self.thread.start()    def cancel(self):      self.thread.cancel() def   printer():    print time.time()  t = myTimer(1,printer)def   defaultButtonPush(*args):  print   'shenmifangke.'def defaultButtonPush2(*args):    t.start()def defaultButtonPush3(*args):  t.cancel()cmds.window( width=150   )cmds.columnLayout( adjustableColumn=True )cmds.button( label='test',   command=defaultButtonPush )cmds.button( label='开启',  command=defaultButtonPush2)cmds.button(   label='关闭',  command=defaultButtonPush3   )cmds.showWindow()后来网上查到这个是可以使用的，这个在cancel后可以重开
    from threading import Timerimport time    class InfiniteTimer():      """A Timer class that does not stop, unless you want it   to."""     def   __init__(self, seconds, target):          self._should_continue = False          self.is_running = False          self.seconds = seconds          self.target = target        self.thread   = None     def   _handle_target(self):          self.is_running = True          self.target()          self.is_running = False          self._start_timer()     def   _start_timer(self):        if   self._should_continue: # Code could have been running when cancel was   called.            self.thread =   Timer(self.seconds, self._handle_target)            self.thread.start()     def start(self):        if not self._should_continue and not   self.is_running:              self._should_continue = True              self._start_timer()          else:              print("Timer already started or running, please wait if you're   restarting.")     def   cancel(self):        if self.thread is   not None:              self._should_continue = False # Just in case thread is running and   cancel fails.            self.thread.cancel()        else:            print("Timer never started   or failed to initialize.")  def   tick():    cmds.polySphere(r=True)    print('shenmifangke') # Example Usaget =   InfiniteTimer(1.5, tick)t.start()
    但是测试后发现很容易崩溃这是什么原因呢
    import threadingimport timeimport maya.utils as utils def example(interval,   ):    global run_timer = True    def your_function_goes_here():        cmds.polySphere(r=True)     while run_timer:         time.sleep(interval)          utils.executeDeferred(your_function_goes_here)        # always use executeDeferred or   evalDeferredInMainThreadWithResult if you're running a thread in Maya! t =   threading.Thread(None, target = example, args = (1,) )t.start()
    然后又找到了上面的代码，完全不会崩溃
    原因就是
    executeDeferred
   
    作者代码里也写到了
    这个就是在建立物体后没有延迟和maya产生的冲突使得maya崩溃了
    然后上面代码当然能进行改造了
    参考网址
      https://stackoverflow.com/questions/12435211/python-threading-timer-repeat-function-every-n-seconds
    https://stackoverflow.com/questions/21164697/how-to-execute-a-maya-mel-procedure-at-regular-intervals
      //download.autodesk.com/global/docs/maya2012/zh_cn/index.html?url=files/Python_Python_in_Maya.htm,topicNumber=d28e683677    

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