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Maya   Calendar
   
   
    Description
    During his last sabbatical, professor M. A. Ya made a surprising discovery   about the old Maya calendar. From an old knotted message, professor   discovered that the Maya civilization used a 365 day long year, called Haab,   which had
     19 months. Each of the first 18   months was 20 days long, and the names of the months were pop, no, zip, zotz,   tzec, xul, yoxkin, mol, chen, yax, zac, ceh, mac, kankin, muan, pax, koyab,   cumhu. Instead of having names, the days of the months were denoted by
 numbers starting from 0 to 19. The   last month of Haab was called uayet and had 5 days denoted by numbers 0, 1,   2, 3, 4. The Maya believed that this month was unlucky, the court of justice   was not in session, the trade stopped, people did not even sweep the
 floor.
    For religious purposes, the Maya used another calendar in which the year   was called Tzolkin (holly year). The year was divided into thirteen periods,   each 20 days long. Each day was denoted by a pair consisting of a number and   the name of the day. They used
     20 names: imix, ik, akbal, kan,   chicchan, cimi, manik, lamat, muluk, ok, chuen, eb, ben, ix, mem, cib, caban,   eznab, canac, ahau and 13 numbers; both in cycles.
   
    Notice that each day has an unambiguous description. For example, at the   beginning of the year the days were described as follows:
   
    1 imix, 2 ik, 3 akbal, 4 kan, 5 chicchan, 6 cimi, 7 manik, 8 lamat, 9   muluk, 10 ok, 11 chuen, 12 eb, 13 ben, 1 ix, 2 mem, 3 cib, 4 caban, 5 eznab,   6 canac, 7 ahau, and again in the next period 8 imix, 9 ik, 10 akbal . .   .
    Years (both Haab and Tzolkin) were denoted by numbers 0, 1, : : : , where   the number 0 was the beginning of the world. Thus, the first day was:
   
    Haab: 0. pop 0
    Tzolkin: 1 imix 0
    Help professor M. A. Ya and write a program for him to convert the dates   from the Haab calendar to the Tzolkin calendar.
   
    Input
    The date in Haab is given in the following format:
    NumberOfTheDay. Month Year
    The first line of the input file contains the number of the input dates in   the file. The next n lines contain n dates in the Haab calendar format, each   in separate line. The year is smaller then 5000.
   
    Output
    The date in Tzolkin should be in the following format:
    Number NameOfTheDay Year
    The first line of the output file contains the number of the output dates.   In the next n lines, there are dates in the Tzolkin calendar format, in the   order corresponding to the input dates.
   
    Sample Input
    3
    10. zac 0
    0. pop 0
    10. zac 1995
   
   
   
   
    Sample Output
    3
    3 chuen 0
    1 imix 0
    9 cimi 2801
   
   
   
    Source Code
    #include <iostream>#include <string>using namespace std;string   HaabMonth[19]={"pop","no","zip","zotz","tzec","xul","yoxkin","mol","chen","yax",                               "zac","ceh","mac","kankin","muan","pax","koyab","cumhu","uayet"};   string TzolkinDate[20]={"imix","ik","akbal","kan","chicchan","cimi","manik","lamat",                          "muluk","ok","chuen","eb","ben","ix","mem","cib","caban","eznab","canac","ahau"};   int toDateNum(string s){ int i=0; while   ((i<=18)&&(s!=HaabMonth[i])) i++; return i;} int toNumOfDay(int   date,string month,int year){ int monthNum=toDateNum(month); return   year*365+monthNum*20+date+1;} int main(){ int   n; cin>>n; cout<<n<<endl; while (n--) { int  HaabDate,HaabYear,TzolkinDateNum,TzolkinYear; string   HaabMonth,TzolkinDateName; char   c; cin>>HaabDate>>c>>HaabMonth>>HaabYear; int   numOfDay=toNumOfDay(HaabDate,HaabMonth,HaabYear); TzolkinYear=(numOfDay-1)/260;                                           //本题对求周期时的除法与减法值得注意 TzolkinDateNum=(numOfDay-1)%13+1;                                       //***** TzolkinDateName=TzolkinDate[(numOfDay-1)%20];                           //***** cout<<TzolkinDateNum<<'   '<<TzolkinDateName<<' '<<TzolkinYear<<endl; } return   0;}    

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